Evaluate ∫0π/2sin(x)ln(sinx)dx\int_0^{\pi/2} \sin(x) \ln(\sin x) dx∫0π/2sin(x)ln(sinx)dx.
ln(2)−1\ln(2) - 1ln(2)−1
1−ln(2)1 - \ln(2)1−ln(2)
ln(2)+1\ln(2) + 1ln(2)+1
0