Evaluate ∫0π/2sin3(x)dx\int_0^{\pi/2} \sin^3(x) dx∫0π/2sin3(x)dx. (Hint: sin3x=sinx(1−cos2x)\sin^3 x = \sin x (1-\cos^2 x)sin3x=sinx(1−cos2x))
2/32/32/3
1/31/31/3
111
3/43/43/4