Evaluate ∫0π/2sin2(x)dx\int_0^{\pi/2} \sin^2(x) dx∫0π/2sin2(x)dx using the identity sin2(x)=1−cos(2x)2\sin^2(x) = \frac{1-\cos(2x)}{2}sin2(x)=21−cos(2x).
\pi/2
\pi/4
1
0