Evaluate ∫0π/2cos3(x)dx\int_0^{\pi/2} \cos^3(x) dx∫0π/2cos3(x)dx using the identity cos2(x)=1−sin2(x)\cos^2(x) = 1 - \sin^2(x)cos2(x)=1−sin2(x).
2/32/32/3
1/31/31/3
4/34/34/3
3/43/43/4