Evaluate ∫01xx2+1dx\int_0^1 \frac{x}{x^2+1} dx∫01x2+1xdx using u-substitution.
ln(2)\ln(2)ln(2)
12ln(2)\frac{1}{2} \ln(2)21ln(2)
ln(2)\ln(\sqrt{2})ln(2)
1−ln(2)1 - \ln(2)1−ln(2)