Evaluate ∫0111+ezdz\int_0^1 \frac{1}{1+e^z} dz∫011+ez1dz.
ln(2)−ln(1+e−1)\ln(2) - \ln(1+e^{-1})ln(2)−ln(1+e−1)
1−ln(1+e)1 - \ln(1+e)1−ln(1+e)
ln(1+e2)\ln(\frac{1+e}{2})ln(21+e)
ln(1+e)−1\ln(1+e) - 1ln(1+e)−1