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Integrals
easy
0:00.0
Evaluate
∫
0
1
(
e
x
+
1
)
d
x
\int_0^1 (e^x + 1) dx
∫
0
1
(
e
x
+
1
)
d
x
.
A
e
e
e
B
e
−
1
e-1
e
−
1
C
e
e
e
D
e
+
1
e+1
e
+
1
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