Evaluate ∫xsec2(x)dx\int x \sec^2(x) dx∫xsec2(x)dx using integration by parts. Let u=xu = xu=x. What is dvdvdv?
sec(x)dx\sec(x) dxsec(x)dx
sec2(x)dx\sec^2(x) dxsec2(x)dx
tan(x)dx\tan(x) dxtan(x)dx
x2dxx^2 dxx2dx