Evaluate ∫1x2−4 dx\int \frac{1}{x^2 - 4} \,dx∫x2−41dx using partial fractions.
14ln∣x−2x+2∣+C\frac{1}{4} \ln |\frac{x-2}{x+2}| + C41ln∣x+2x−2∣+C
14ln∣x+2x−2∣+C\frac{1}{4} \ln |\frac{x+2}{x-2}| + C41ln∣x−2x+2∣+C
12ln∣x−2x+2∣+C\frac{1}{2} \ln |\frac{x-2}{x+2}| + C21ln∣x+2x−2∣+C
12ln∣x2−4∣+C\frac{1}{2} \ln |x^2-4| + C21ln∣x2−4∣+C