Evaluate ∫1(x+1)(x+2) dx\int \frac{1}{(x+1)(x+2)}\,dx∫(x+1)(x+2)1dx.
ln∣x+1x+2∣+C\ln\left|\frac{x+1}{x+2}\right| + Clnx+2x+1+C
ln∣(x+1)(x+2)∣+C\ln|(x+1)(x+2)| + Cln∣(x+1)(x+2)∣+C
−1(x+1)(x+2)+C\frac{-1}{(x+1)(x+2)} + C(x+1)(x+2)−1+C
ln∣x+1∣−ln∣x+2∣+C\ln|x+1| - \ln|x+2| + Cln∣x+1∣−ln∣x+2∣+C (same as (a))