Evaluate ∫(6x2+4x−3) dx\int (6x^2 + 4x - 3)\,dx∫(6x2+4x−3)dx.
2x3+2x2−3x+C2x^3 + 2x^2 - 3x + C2x3+2x2−3x+C
6x3+4x2−3x+C6x^3 + 4x^2 - 3x + C6x3+4x2−3x+C
12x+4+C12x + 4 + C12x+4+C
2x3+2x2+C2x^3 + 2x^2 + C2x3+2x2+C