Evaluate ∫(4x−1)dx\int (4x - 1) dx∫(4x−1)dx given that F(1)=3F(1) = 3F(1)=3.
2x2−x+22x^2 - x + 22x2−x+2
2x2−x+12x^2 - x + 12x2−x+1
4x2−x4x^2 - x4x2−x
2x2−x+32x^2 - x + 32x2−x+3