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Foundations
easy
0:00.0
Evaluate
5
−
2
⋅
∣
x
−
3
∣
5 - 2 \cdot |x-3|
5
−
2
⋅
∣
x
−
3∣
when
x
=
7
x=7
x
=
7
.
A
−
3
-3
−
3
B
3
3
3
C
13
13
13
D
1
1
1
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