Divide: x2−1x+3÷x−1x+3\dfrac{x^2 - 1}{x + 3} \div \dfrac{x - 1}{x + 3}x+3x2−1÷x+3x−1.
x+1x + 1x+1
x−1x - 1x−1
x2−1x−1\dfrac{x^2-1}{x-1}x−1x2−1
1x+1\dfrac{1}{x+1}x+11