Divide: x+1x−3÷(x+1)\dfrac{x+1}{x-3} \div (x + 1)x−3x+1÷(x+1).
1x−3\dfrac{1}{x - 3}x−31
x+1x−3\dfrac{x+1}{x-3}x−3x+1
(x−3)(x+1)(x - 3)(x + 1)(x−3)(x+1)
x−3x - 3x−3