Determine which series diverges at its endpoint(s). ∑n=1∞(−1)nxnnat x=−1\sum_{n=1}^{\infty} \frac{(-1)^n x^n}{n} \quad \text{at } x = -1∑n=1∞n(−1)nxnat x=−1
Converges by the alternating series test
Diverges by the divergence test
Conditionally converges
Converges absolutely