Determine the vertex of the parabola y2−6y−4x+13=0y^2 - 6y - 4x + 13 = 0y2−6y−4x+13=0.
(1,3)(1, 3)(1,3)
(3,1)(3, 1)(3,1)
(−1,3)(-1, 3)(−1,3)
(1,−3)(1, -3)(1,−3)