Determine the value of xxx that satisfies the equation 22x+2x+2−32=02^{2x} + 2^{x+2} - 32 = 022x+2x+2−32=0.
x=2x = 2x=2
x=1x = 1x=1
x=3x = 3x=3
x=0x = 0x=0