Determine the value of xxx that satisfies logx(2)+logx(4)+logx(8)=6\log_x(2) + \log_x(4) + \log_x(8) = 6logx(2)+logx(4)+logx(8)=6.
x=2x = \sqrt{2}x=2
x=2x = 2x=2
x=4x = 4x=4
x=646x = \sqrt[6]{64}x=664