Determine the value of xxx that satisfies log3(x+4)−log3(x−2)=2\log_3(x+4) - \log_3(x-2) = 2log3(x+4)−log3(x−2)=2.
x=3x = 3x=3
x=4x = 4x=4
x=5x = 5x=5
x=6x = 6x=6