Determine the value of xxx that satisfies 2x+2−2x2x−2x−1=6\frac{2^{x+2} - 2^x}{2^x - 2^{x-1}} = 62x−2x−12x+2−2x=6.
x=1x = 1x=1
x=2x = 2x=2
x=3x = 3x=3
x=0x = 0x=0