Determine the value of xxx that satisfies 1log2x+1log3x+1log4x=1\frac{1}{\log_2 x} + \frac{1}{\log_3 x} + \frac{1}{\log_4 x} = 1log2x1+log3x1+log4x1=1.
24
12
6
2^1 \cdot 3^1 \cdot 4^1