Determine the value of xxx such that e2x−5ex+6=0e^{2x} - 5e^x + 6 = 0e2x−5ex+6=0.
x=ln2x = \ln 2x=ln2 or x=ln3x = \ln 3x=ln3
x=2x = 2x=2 or x=3x = 3x=3
x=e2x = e^2x=e2 or x=e3x = e^3x=e3
x=ln5x = \ln 5x=ln5