Determine the value of the parameter aaa such that the integral ∫01(ax2+x)dx=2\int_{0}^{1} (ax^2 + x) dx = 2∫01(ax2+x)dx=2.
a=3a = 3a=3
a=6a = 6a=6
a=9a = 9a=9
a=4a = 4a=4