Determine the value of the integral I=∫0∞dx(x2+1)(x2+9)I = \int_{0}^{\infty} \frac{dx}{(x^2+1)(x^2+9)}I=∫0∞(x2+1)(x2+9)dx.
π24\frac{\pi}{24}24π
π12\frac{\pi}{12}12π
π8\frac{\pi}{8}8π
π16\frac{\pi}{16}16π