Determine the value of the double integral ∫01∫0xex2dydx\int_0^1 \int_0^x e^{x^2} dy dx∫01∫0xex2dydx.
12(e−1)\frac{1}{2}(e - 1)21(e−1)
e−1e - 1e−1
12(e+1)\frac{1}{2}(e + 1)21(e+1)
eee