Determine the value of kkk such that the differential equation (3x2y+2xy2)dx+(x3+kx2y)dy=0(3x^2y + 2xy^2)dx + (x^3 + k x^2y)dy = 0(3x2y+2xy2)dx+(x3+kx2y)dy=0 is exact.
k=1k = 1k=1
k=2k = 2k=2
k=3k = 3k=3
k=4k = 4k=4