Determine the value of kkk such that limx→0cos(kx)−1x2=−8\lim_{x \to 0} \frac{\cos(kx) - 1}{x^2} = -8limx→0x2cos(kx)−1=−8.
k=4k = 4k=4
k=±4k = \pm 4k=±4
k=16k = 16k=16
k=±8k = \pm 8k=±8