Determine the value of kkk such that f(x)={4x+kx<13x=1x2+1x>1f(x) = \begin{cases} 4x + k & x < 1 \\ 3 & x = 1 \\ x^2 + 1 & x > 1 \end{cases}f(x)=⎩⎨⎧4x+k3x2+1x<1x=1x>1 is continuous at x=1x = 1x=1.
k=1k = 1k=1
k=2k = 2k=2
k=−1k = -1k=−1
k=0k = 0k=0