Determine the value of kkk such that 2x2+kx−10x−4\frac{2x^2 + kx - 10}{x-4}x−42x2+kx−10 has a remainder of 666 when divided.
k=2k = 2k=2
k=−1k = -1k=−1
k=4k = 4k=4
k=−4k = -4k=−4