Determine the value of kkk for which f(x)={sin(kx)xx<03x+2k2x≥0f(x) = \begin{cases} \frac{\sin(kx)}{x} & x < 0 \\ 3x + 2k^2 & x \ge 0 \end{cases}f(x)={xsin(kx)3x+2k2x<0x≥0 is continuous at x=0x=0x=0.
k=1k=1k=1
k=−2k=-2k=−2
k=1k=1k=1 and k=−2k=-2k=−2
No such kkk exists