Determine the value of ∫0π/4tan2(x)dx\int_0^{\pi/4} \tan^2(x) dx∫0π/4tan2(x)dx. (Hint: 1+tan2(x)=sec2(x)1 + \tan^2(x) = \sec^2(x)1+tan2(x)=sec2(x))
1−π41 - \frac{\pi}{4}1−4π
π4−1\frac{\pi}{4} - 14π−1
1+π41 + \frac{\pi}{4}1+4π
π2\frac{\pi}{2}2π