Determine the type of critical point for the autonomous equation dydx=(y−2)2(y+1)\frac{dy}{dx} = (y-2)^2(y+1)dxdy=(y−2)2(y+1).
y=2y=2y=2 is unstable, y=−1y=-1y=−1 is stable.
y=2y=2y=2 is semi-stable, y=−1y=-1y=−1 is unstable.
y=2y=2y=2 is stable, y=−1y=-1y=−1 is unstable.
y=2y=2y=2 is semi-stable, y=−1y=-1y=−1 is stable.