Determine the truth value of the statement: (∀x∈Z+)(∃y∈Z+)(x⋅y=1)(\forall x \in \mathbb{Z}^+)(\exists y \in \mathbb{Z}^+)(x \cdot y = 1)(∀x∈Z+)(∃y∈Z+)(x⋅y=1).
True
False
True only for x=1
True for all even x