Determine the sum of the series ∑n=0∞(−1)nπ2n42n(2n)!\sum_{n=0}^{\infty} \frac{(-1)^n \pi^{2n}}{4^{2n} (2n)!}∑n=0∞42n(2n)!(−1)nπ2n.
1/21/21/2
2/2\sqrt{2}/22/2
3/2\sqrt{3}/23/2
000