Determine the solution to the inequality x2−5x+4x2+2x−8≤0\frac{x^2 - 5x + 4}{x^2 + 2x - 8} \leq 0x2+2x−8x2−5x+4≤0.
[1,4][1, 4][1,4]
(−4,1]∪(2,4](-4, 1] \cup (2, 4](−4,1]∪(2,4]
(−∞,−4)∪[1,2)∪[4,∞)(-\infty, -4) \cup [1, 2) \cup [4, \infty)(−∞,−4)∪[1,2)∪[4,∞)
(−4,2)(-4, 2)(−4,2)