Determine the solution of y′=yxy' = \frac{y}{x}y′=xy with y(1)=2y(1) = 2y(1)=2.
y=2xy = 2xy=2x
y=x2y = x^2y=x2
y=2x2y = 2x^2y=2x2
y=x+1y = x+1y=x+1