Determine the solution of y′=3x2y' = 3x^2y′=3x2 with y(0)=5y(0) = 5y(0)=5.
y=x3+5y = x^3 + 5y=x3+5
y=x3y = x^3y=x3
y=3x3+5y = 3x^3 + 5y=3x3+5
y=x3+2y = x^3 + 2y=x3+2