Determine the solution of dydx=cos(x)\frac{dy}{dx} = \cos(x)dxdy=cos(x) passing through the origin (0,0)(0, 0)(0,0).
y=sin(x)+1y = \sin(x) + 1y=sin(x)+1
y=cos(x)y = \cos(x)y=cos(x)
y=sin(x)y = \sin(x)y=sin(x)
y=−sin(x)y = -\sin(x)y=−sin(x)