Determine the set of xxx values for which x2−16x+2≤0\frac{x^2-16}{x+2} \leq 0x+2x2−16≤0.
(−∞,−4]∪[−2,4](-\infty, -4] \cup [-2, 4](−∞,−4]∪[−2,4]
(−∞,−4]∪(−2,4](-\infty, -4] \cup (-2, 4](−∞,−4]∪(−2,4]
[−4,−2)∪[4,∞)[-4, -2) \cup [4, \infty)[−4,−2)∪[4,∞)
None of the above