Determine the set of values for xxx such that x2−9x2−1≤0\frac{x^2-9}{x^2-1} \leq 0x2−1x2−9≤0.
(−3,−1)∪(1,3)(-3, -1) \cup (1, 3)(−3,−1)∪(1,3)
[-3, -1) \cup (1, 3]
(−∞,−3]∪[3,∞)(-\infty, -3] \cup [3, \infty)(−∞,−3]∪[3,∞)
(−1,1)(-1, 1)(−1,1)