Determine the set of all xxx values that satisfy the inequality x2−4x+3x2−9≤0\frac{x^2 - 4x + 3}{x^2 - 9} \leq 0x2−9x2−4x+3≤0.
(−3,1]∪(3,∞)(-3, 1] \cup (3, \infty)(−3,1]∪(3,∞)
(−3,1]∪(3,∞)(-3, 1] \cup (3, \infty)(−3,1]∪(3,∞) is wrong; correct is (−3,1]∪[3,∞)(-3, 1] \cup [3, \infty)(−3,1]∪[3,∞)
(−∞,−3)∪[1,3)(-\infty, -3) \cup [1, 3)(−∞,−3)∪[1,3)