Determine the set of all real values of xxx that satisfy the inequality x2−x−6x2+2x−8<0\frac{x^2 - x - 6}{x^2 + 2x - 8} < 0x2+2x−8x2−x−6<0.
(−4,−2)∪(2,3)(-4, -2) \cup (2, 3)(−4,−2)∪(2,3)
(−2,2)∪(3,4)(-2, 2) \cup (3, 4)(−2,2)∪(3,4)
(−4,−3)∪(2,3)(-4, -3) \cup (2, 3)(−4,−3)∪(2,3)
(−3,−2)∪(2,4)(-3, -2) \cup (2, 4)(−3,−2)∪(2,4)