Determine the set of all real values of xxx that satisfy the inequality: x3−3x2−4xx2−9≤0\frac{x^3 - 3x^2 - 4x}{x^2 - 9} \leq 0x2−9x3−3x2−4x≤0
x∈(−3,−1]∪(0,3)∪[4,∞)x \in (-3, -1] \cup (0, 3) \cup [4, \infty)x∈(−3,−1]∪(0,3)∪[4,∞)
x∈(−∞,−3)∪[−1,0]∪(3,4]x \in (-\infty, -3) \cup [-1, 0] \cup (3, 4]x∈(−∞,−3)∪[−1,0]∪(3,4]
x∈(−3,−1]∪[0,3)∪[4,∞)x \in (-3, -1] \cup [0, 3) \cup [4, \infty)x∈(−3,−1]∪[0,3)∪[4,∞)
x∈(−∞,−3)∪[−1,0]∪[3,4]x \in (-\infty, -3) \cup [-1, 0] \cup [3, 4]x∈(−∞,−3)∪[−1,0]∪[3,4]