Determine the range of xxx such that 2x+3≥x\sqrt{2x+3} \ge x2x+3≥x.
x≥−1.5x \ge -1.5x≥−1.5
−1.5≤x≤3-1.5 \le x \le 3−1.5≤x≤3
x≥3x \ge 3x≥3
x≤3x \le 3x≤3