Determine the radius of convergence RRR of the power series ∑n=1∞(2n)!(n!)2xn\sum_{n=1}^{\infty} \frac{(2n)!}{(n!)^2} x^n∑n=1∞(n!)2(2n)!xn.
R=14R = \frac{1}{4}R=41
R=1R = 1R=1
R=4R = 4R=4
R=0R = 0R=0