Determine the radius of convergence RRR for ∑n=0∞(2n)!(n!)2xn\sum_{n=0}^{\infty} \frac{(2n)!}{(n!)^2} x^n∑n=0∞(n!)2(2n)!xn.
R=1R = 1R=1
R=1/4R = 1/4R=1/4
R=1/2R = 1/2R=1/2
R=0R = 0R=0