Determine the radius of convergence for ∑n=1∞(2x+4)nn2\sum_{n=1}^{\infty} \frac{(2x+4)^n}{n^2}∑n=1∞n2(2x+4)n.
R=2R = 2R=2
R=1R = 1R=1
R=1/2R = 1/2R=1/2
R=4R = 4R=4