Determine the partial derivative hy(x,y)h_y(x, y)hy(x,y) of the function h(x,y)=x+1yh(x, y) = \frac{x+1}{y}h(x,y)=yx+1.
−x+1y2-\frac{x+1}{y^2}−y2x+1
1y\frac{1}{y}y1
x+1y2\frac{x+1}{y^2}y2x+1
−1y2-\frac{1}{y^2}−y21