Determine the partial derivative fyf_yfy of the function f(x,y)=xyf(x,y) = x^yf(x,y)=xy for x>0x > 0x>0.
xyln(x)x^y \ln(x)xyln(x)
yxy−1y x^{y-1}yxy−1
xyln(y)x^y \ln(y)xyln(y)
yxy−1ln(x)y x^{y-1} \ln(x)yxy−1ln(x)